1.f:[0,1]→[0,1]f:[0,1]\to[0,1]f:[0,1]→[0,1] continuous, x2+f(x)2≤1x^2+f(x)^2\le1x2+f(x)2≤1, ∫01f=π/4\int_0^1 f = \pi/4∫01f=π/4. Then ∫1/21/2f(x)1−x2dx\int_{1/2}^{1/\sqrt2}\frac{f(x)}{1-x^2}dx∫1/21/21−x2f(x)dx equalsa.π/12\pi/12π/12b.π/15\pi/15π/15c.2−12π\frac{\sqrt2-1}{2}\pi22−1πd.π/6\pi/6π/6Login to continueOnly logged in users canattempt or see the solution.
