1.A body of mass 10 kg10\,\text{kg}10kg is acted upon by a force given by the equation F=(3t2−30)F = (3t^2 - 30)F=(3t2−30) newtons. The initial velocity of the body is 10 m/s10\,\text{m/s}10m/s. The velocity of the body after 555 s isa.4.5 m/s4.5\,\text{m/s}4.5m/sb.6 m/s6\,\text{m/s}6m/sc.7.5 m/s7.5\,\text{m/s}7.5m/sd.5 m/s5\,\text{m/s}5m/sLogin to continueOnly logged in users canattempt or see the solution.