1.The value of limx→1xtan{x}x−1\displaystyle\lim_{x\to1}\frac{x\tan\{x\}}{x-1}x→1limx−1xtan{x} is equal to (where {x}\{x\}{x} denotes fractional part)a.−1-1−1b.000c.111d.Does not existLogin to continueOnly logged in users canattempt or see the solution.