1.When a voltage v=2002sin(ωt+15°)v = 200\sqrt{2}\sin(\omega t + 15°)v=2002sin(ωt+15°) is applied to an AC circuit, the current in the circuit is found to be i=2sin(ωt+π/4)i = 2\sin(\omega t + \pi/4)i=2sin(ωt+π/4). The average power consumed in the circuit isa.200 W200\,\text{W}200Wb.4002 W400\sqrt{2}\,\text{W}4002Wc.1006 W100\sqrt{6}\,\text{W}1006Wd.2002 W200\sqrt{2}\,\text{W}2002WLogin to continueOnly logged in users canattempt or see the solution.