1.Let ana_nan, n∈Nn \in \mathbb{N}n∈N, be an A.P. with common difference ddd and all non-zero terms. As nnn approaches infinity, the sum 1a1a2+1a2a3+⋯+1anan+1+⋯\dfrac{1}{a_1 a_2} + \dfrac{1}{a_2 a_3} + \cdots + \dfrac{1}{a_n a_{n+1}} + \cdotsa1a21+a2a31+⋯+anan+11+⋯ will approacha.1a1d\dfrac{1}{a_1 d}a1d1b.2a1d\dfrac{2}{a_1 d}a1d2c.12a1d\dfrac{1}{2 a_1 d}2a1d1d.a1da_1 da1dLogin to continueOnly logged in users canattempt or see the solution.