1.If the center and radius of the circle ∣z−2i∣=2|z - 2i| = 2∣z−2i∣=2 are respectively (α,β)(\alpha, \beta)(α,β) and γ\gammaγ, then 3(α+β+γ)3(\alpha + \beta + \gamma)3(α+β+γ) is equal to:a.111111b.999c.101010d.121212Login to continueOnly logged in users canattempt or see the solution.
