1.The parabola with directrix x+2y−1=0x + 2y - 1 = 0x+2y−1=0 and focus (1,0)(1, 0)(1,0) isa.4x2−4xy+y2−8x+4y+4=04x^2 - 4xy + y^2 - 8x + 4y + 4 = 04x2−4xy+y2−8x+4y+4=0b.4x2+4xy+y2−8x+4y+4=04x^2 + 4xy + y^2 - 8x + 4y + 4 = 04x2+4xy+y2−8x+4y+4=0c.4x2+4xy+y2+8x−4y+4=04x^2 + 4xy + y^2 + 8x - 4y + 4 = 04x2+4xy+y2+8x−4y+4=0d.4x2−4xy+y2−8x−4y+4=04x^2 - 4xy + y^2 - 8x - 4y + 4 = 04x2−4xy+y2−8x−4y+4=0Login to continueOnly logged in users canattempt or see the solution.
