1.E∘(Ni2+/Ni)=−0.25 VE^\circ(\text{Ni}^{2+}/\text{Ni}) = -0.25\,\text{V}E∘(Ni2+/Ni)=−0.25V, E∘(Au3+/Au)=1.50 VE^\circ(\text{Au}^{3+}/\text{Au}) = 1.50\,\text{V}E∘(Au3+/Au)=1.50V. The standard emf of the voltaic cellNi (s) ∣ Ni(aq)2+ (1.0 M) ∥ Au(aq)3+ (1.0 M) ∣ Au (s)\text{Ni}\,(\text{s})\,|\,\text{Ni}^{2+}_{(\text{aq})}\,(1.0\,\text{M})\,\|\,\text{Au}^{3+}_{(\text{aq})}\,(1.0\,\text{M})\,|\,\text{Au}\,(\text{s})Ni(s)∣Ni(aq)2+(1.0M)∥Au(aq)3+(1.0M)∣Au(s)is:a.1.25 V1.25\,\text{V}1.25Vb.−1.75 V-1.75\,\text{V}−1.75Vc.1.75 V1.75\,\text{V}1.75Vd.4.0 V4.0\,\text{V}4.0VLogin to continueOnly logged in users canattempt or see the solution.
