1.If α\alphaα and β\betaβ are the roots of the equation x2+x+1=0x^2 + x + 1 = 0x2+x+1=0, then the equation whose roots are α19\alpha^{19}α19 and β7\beta^{7}β7 isa.x2−x−1=0x^2 - x - 1 = 0x2−x−1=0b.x2−x+1=0x^2 - x + 1 = 0x2−x+1=0c.x2+x−1=0x^2 + x - 1 = 0x2+x−1=0d.x2+x+1=0x^2 + x + 1 = 0x2+x+1=0Login to continueOnly logged in users canattempt or see the solution.
