1.The inequality sin−1(sin5)>x2−4x\sin^{-1}(\sin 5) > x^2 - 4xsin−1(sin5)>x2−4x holds fora.x∈(2−9−2π, 2+9−2π)x \in (2 - \sqrt{9 - 2\pi},\; 2 + \sqrt{9 - 2\pi})x∈(2−9−2π,2+9−2π)b.x>2+9−2πx > 2 + \sqrt{9 - 2\pi}x>2+9−2πc.x<2−9−2πx < 2 - \sqrt{9 - 2\pi}x<2−9−2πd.x∈ϕx \in \phix∈ϕLogin to continueOnly logged in users canattempt or see the solution.
