1.Let ⋄∈{∧,∨,⇒,⇔}\diamond \in \{\wedge, \vee, \Rightarrow, \Leftrightarrow\}⋄∈{∧,∨,⇒,⇔} be such that (p⋄q)⇔((p∨q)⋄q)(p \diamond q) \Leftrightarrow ((p \vee q) \diamond q)(p⋄q)⇔((p∨q)⋄q) is a tautology. Then ⋄\diamond⋄ is equal to:a.⇔\Leftrightarrow⇔b.∨\vee∨c.⇒\Rightarrow⇒d.∧\wedge∧Login to continueOnly logged in users canattempt or see the solution.
