1.f(x)={2x2+1,x≤14x3−1,x>1f(x)=\begin{cases}2x^2+1,&x\le1\\4x^3-1,&x>1\end{cases}f(x)={2x2+1,4x3−1,x≤1x>1. Then ∫02f(x)dx\int_0^2 f(x)dx∫02f(x)dx isa.473\frac{47}{3}347b.503\frac{50}{3}350c.13\frac1331d.472\frac{47}{2}247Login to continueOnly logged in users canattempt or see the solution.