1.Let f(x)={ax+1,x<13,x=1bx2+1,x>1f(x) = \begin{cases} ax + 1, & x < 1 \\ 3, & x = 1 \\ bx^2 + 1, & x > 1 \end{cases}f(x)=⎩⎨⎧ax+1,3,bx2+1,x<1x=1x>1. If f(x)f(x)f(x) is continuous at x=1x = 1x=1, then (a−b)(a - b)(a−b) is equal to:a.000b.111c.222d.444Login to continueOnly logged in users canattempt or see the solution.
