1.The Boolean expression (∼(p∧q))∨q(\sim(p \wedge q)) \vee q(∼(p∧q))∨q is equivalent to:a.q⇒(p∧q)q \Rightarrow (p \wedge q)q⇒(p∧q)b.p⇒qp \Rightarrow qp⇒qc.∼(p∨q)\sim(p \vee q)∼(p∨q)d.p⇒(p∨q)p \Rightarrow (p \vee q)p⇒(p∨q)Login to continueOnly logged in users canattempt or see the solution.
