1.The three sides of a right angled triangle are in GP (geometric progression). If the two acute angles be α\alphaα and β\betaβ, then tanα\tan \alphatanα and tanβ\tan \betatanβ area.5+12\frac{\sqrt{5}+1}{2}25+1 and 5−12\frac{\sqrt{5}-1}{2}25−1b.5−12\frac{\sqrt{5}-1}{2}25−1 and 5+12\frac{\sqrt{5}+1}{2}25+1c.5\sqrt{5}5 and 15\frac{1}{\sqrt{5}}51d.52\frac{\sqrt{5}}{2}25 and 25\frac{2}{\sqrt{5}}52Login to continueOnly logged in users canattempt or see the solution.