1.If foot of perpendicular from (0,0,0)(0,0,0)(0,0,0) to a plane is (1,2,3)(1,2,3)(1,2,3), then the plane equation isa.2x+y+3z=142x+y+3z=142x+y+3z=14b.x+2y+3z=14x+2y+3z=14x+2y+3z=14c.x+2y+3z+14=0x+2y+3z+14=0x+2y+3z+14=0d.x+2y−3z=14x+2y-3z=14x+2y−3z=14Login to continueOnly logged in users canattempt or see the solution.
