1.The value of limn→∞[x]+[22x]+[32x]+…+[n2x]12+22+32+…+n2\displaystyle\lim_{n\to\infty}\frac{[x]+[2^2x]+[3^2x]+\ldots+[n^2x]}{1^2+2^2+3^2+\ldots+n^2}n→∞lim12+22+32+…+n2[x]+[22x]+[32x]+…+[n2x] is equal to (where [x][x][x] represents GIF)a.xxxb.2x2x2xc.x/2x/2x/2d.x/6x/6x/6Login to continueOnly logged in users canattempt or see the solution.
