1.If zzz is a complex number satisfying the equation ∣z−(1+i)∣2=2|z - (1 + i)|^2 = 2∣z−(1+i)∣2=2 and ω=2z\omega = \frac{2}{z}ω=z2, then the locus traced by ω\omegaω in the complex plane isa.x−y−1=0x - y - 1 = 0x−y−1=0b.x+y−1=0x + y - 1 = 0x+y−1=0c.x−y+1=0x - y + 1 = 0x−y+1=0d.x+y+1=0x + y + 1 = 0x+y+1=0Login to continueOnly logged in users canattempt or see the solution.
