1.The point (3,−4)(3,-4)(3,−4) lies on both circles x2+y2−2x+8y+13=0x^2+y^2-2x+8y+13=0x2+y2−2x+8y+13=0 and x2+y2−4x+6y+11=0x^2+y^2-4x+6y+11=0x2+y2−4x+6y+11=0. Then the angle between the circles isa.60∘60^\circ60∘b.tan−1(1)\tan^{-1}(1)tan−1(1)c.tan−1(32)\tan^{-1}\left(\frac{3}{2}\right)tan−1(23)d.135∘135^\circ135∘Login to continueOnly logged in users canattempt or see the solution.
