1.Let the observations xix_ixi (1≤i≤101 \leq i \leq 101≤i≤10) satisfy ∑i=110(xi−5)=10\sum_{i=1}^{10}(x_i-5)=10∑i=110(xi−5)=10, ∑i=110(xi−5)2=40\sum_{i=1}^{10}(x_i-5)^2=40∑i=110(xi−5)2=40. If μ\muμ and λ\lambdaλ are the mean and variance of x1−3,x2−3,…,x10−3x_1-3, x_2-3, \ldots, x_{10}-3x1−3,x2−3,…,x10−3, then the ordered pair (μ,λ)(\mu, \lambda)(μ,λ) isa.(3, 3)b.(6, 3)c.(6, 6)d.(3, 6)Login to continueOnly logged in users canattempt or see the solution.
