1.If the sum of the series 1⋅(1+d)+(1+d)(1+2d)+…+(1+9d)(1+10d)1 \cdot (1+d) + (1+d)(1+2d) + \ldots + (1+9d)(1+10d)1⋅(1+d)+(1+d)(1+2d)+…+(1+9d)(1+10d) is equal to 555, then 50d50d50d is equal toa.101010b.555c.151515d.202020Login to continueOnly logged in users canattempt or see the solution.
