1.The equation of the curve passing through the origin and satisfying the differential equation (1+x2) dy+2xy dx=4x2 dx(1 + x^2)\,dy + 2xy\,dx = 4x^2\,dx(1+x2)dy+2xydx=4x2dx isa.(1+x2)y=x3(1 + x^2)y = x^3(1+x2)y=x3b.3(1+x2)y=2x33(1 + x^2)y = 2x^33(1+x2)y=2x3c.(1+x2)y=3x3(1 + x^2)y = 3x^3(1+x2)y=3x3d.3(1+x2)y=4x33(1 + x^2)y = 4x^33(1+x2)y=4x3Login to continueOnly logged in users canattempt or see the solution.
