1.Equation of the plane through (1,1,1)(1,1,1)(1,1,1) and (1,−1,−1)(1,-1,-1)(1,−1,−1) and perpendicular to 2x−y+z+5=02x-y+z+5=02x−y+z+5=0 isa.2x+5y+z+8=02x+5y+z+8=02x+5y+z+8=0b.x+y−z−1=0x+y-z-1=0x+y−z−1=0c.2x+5y+z+4=02x+5y+z+4=02x+5y+z+4=0d.x−y+z−1=0x-y+z-1=0x−y+z−1=0Login to continueOnly logged in users canattempt or see the solution.
