1.If the system of equationsx+y+z=6x + y + z = 6x+y+z=62x+5y+az=β2x + 5y + az = \beta2x+5y+az=βx+2y+3z=14x + 2y + 3z = 14x+2y+3z=14has infinitely many solutions, then a+βa + \betaa+β is equal to:a.888b.363636c.444444d.484848Login to continueOnly logged in users canattempt or see the solution.
