1.The magnetic field of a plane electromagnetic wave is given by B⃗=3×10−8cos(1.6×103x+48×1010t)j^\vec{B} = 3 \times 10^{-8} \cos (1.6 \times 10^3 x + 48 \times 10^{10} t) \hat{j}B=3×10−8cos(1.6×103x+48×1010t)j^, then the associated electric field will be:a.3×10−8cos(1.6×103x+48×1010t)i^3 \times 10^{-8} \cos (1.6 \times 10^3 x + 48 \times 10^{10} t) \hat{i}3×10−8cos(1.6×103x+48×1010t)i^ V/mb.3×10−8sin(1.6×103x+48×1010t)i^3 \times 10^{-8} \sin (1.6 \times 10^3 x + 48 \times 10^{10} t) \hat{i}3×10−8sin(1.6×103x+48×1010t)i^ V/mc.9sin(1.6×103x−48×1010t)k^9 \sin (1.6 \times 10^3 x - 48 \times 10^{10} t) \hat{k}9sin(1.6×103x−48×1010t)k^ V/md.9cos(1.6×103x+48×1010t)k^9 \cos (1.6 \times 10^3 x + 48 \times 10^{10} t) \hat{k}9cos(1.6×103x+48×1010t)k^ V/mLogin to continueOnly logged in users canattempt or see the solution.
