1.If the numbers appeared on the two throws of a fair six-faced die are α\alphaα and β\betaβ, then the probability that x2+αx+β>0x^2 + \alpha x + \beta > 0x2+αx+β>0, for all x∈Rx \in \mathbb{R}x∈R, is:a.1736\dfrac{17}{36}3617b.1936\dfrac{19}{36}3619c.14\dfrac{1}{4}41d.1180\dfrac{1}{180}1801Login to continueOnly logged in users canattempt or see the solution.
