1.If a1,a2,a3,…a_1, a_2, a_3, \ldotsa1,a2,a3,… and b1,b2,b3,…b_1, b_2, b_3, \ldotsb1,b2,b3,… are A.P.'s with a12=b103,a103=b12=1a_{12} = b_{103}, a_{103} = b_{12} = 1a12=b103,a103=b12=1 and a1⋅b1=1a_1 \cdot b_1 = 1a1⋅b1=1, then a4⋅b4a_4 \cdot b_4a4⋅b4 is equal to:a.78\dfrac{7}{8}87b.289\dfrac{28}{9}928c.2827\dfrac{28}{27}2728d.233\dfrac{2}{33}332Login to continueOnly logged in users canattempt or see the solution.
