1.If the general solution of y′=yx+Φ(xy)y' = \frac{y}{x} + \Phi\left(\frac{x}{y}\right)y′=xy+Φ(yx), for some function Φ\PhiΦ, is given by yln∣cx∣=xy\ln|cx| = xyln∣cx∣=x, where ccc is an arbitrary constant, then Φ(2)\Phi(2)Φ(2) is equal toa.444b.1/41/41/4c.−4-4−4d.−1/4-1/4−1/4Login to continueOnly logged in users canattempt or see the solution.