1.
Using the data provided, find the value of the equilibrium constant for the following reaction at 298 K and 1 atm pressure.

NO(g)+12O2(g)NO2(g)\text{NO}(g) + \frac{1}{2}\text{O}_2(g) \rightleftharpoons \text{NO}_2(g)

ΔfH(NO(g))=90.4\Delta_f H^\circ (\text{NO}(g)) = 90.4 kJ mol1^{-1}

ΔfH(NO2(g))=32.48\Delta_f H^\circ (\text{NO}_2(g)) = 32.48 kJ mol1^{-1}

ΔS\Delta S^\circ at 298 K = 70.8-70.8 J K1^{-1} mol1^{-1}

[Given: antilog(0.50)=3.162(0.50) = 3.162]