1.90Th232→82Pb208_{90}Th^{232} \to _{82}Pb^{208}90Th232→82Pb208. The number of α\alphaα and β\betaβ-particles emitted during the above reaction isa.8α8\alpha8α and 4β4\beta4βb.8α8\alpha8α and 16β16\beta16βc.4α4\alpha4α and 2β2\beta2βd.6α6\alpha6α and 4β4\beta4βLogin to continueOnly logged in users canattempt or see the solution.
