1.If the solubility of AgCl\text{AgCl}AgCl (formula mass =143= 143=143) in water at 25°C25°\text{C}25°C is 1.43×10−4 g/100 mL1.43 \times 10^{-4}\,\text{g}/100\,\text{mL}1.43×10−4g/100mL of solution, then the value of KspK_{sp}Ksp will be:a.1×10−51 \times 10^{-5}1×10−5b.2×10−52 \times 10^{-5}2×10−5c.1×10−101 \times 10^{-10}1×10−10d.2×10−102 \times 10^{-10}2×10−10Login to continueOnly logged in users canattempt or see the solution.
