1.If in triangle ABCABCABC, A≡(1,10)A \equiv (1,10)A≡(1,10), circumcentre ≡(−13,23)\equiv \left(-\frac{1}{3}, \frac{2}{3}\right)≡(−31,32) and orthocentre ≡(113,43)\equiv \left(\frac{11}{3}, \frac{4}{3}\right)≡(311,34) then the co-ordinates of mid-point of side opposite to AAA is-a.(1,−113)\left(1, -\frac{11}{3}\right)(1,−311)b.(1,5)(1,5)(1,5)c.(1,−3)(1,-3)(1,−3)d.(1,6)(1,6)(1,6)Login to continueOnly logged in users canattempt or see the solution.
