1.Total number of 6-digit numbers in which only and all the five digits 1, 3, 5, 7 and 9 appears, isa.12(6!)\tfrac{1}{2}(6!)21(6!)b.6!6!6!c.565^656d.52(6!)\tfrac{5}{2}(6!)25(6!)Login to continueOnly logged in users canattempt or see the solution.