1.CH3CH=CH−C6H4-OCH3\text{CH}_3\text{CH}=\text{CH}-\text{C}_6\text{H}_4\text{-OCH}_3CH3CH=CH−C6H4-OCH3 on reaction with HBr gives –a.CH3CH(Br)CH(Br)C6H4-OCH3\text{CH}_3\text{CH}(\text{Br})\text{CH}(\text{Br})\text{C}_6\text{H}_4\text{-OCH}_3CH3CH(Br)CH(Br)C6H4-OCH3b.CH3CH(Br)CH(Br)C6H4-Br\text{CH}_3\text{CH}(\text{Br})\text{CH}(\text{Br})\text{C}_6\text{H}_4\text{-Br}CH3CH(Br)CH(Br)C6H4-Br (ring-brominated product)c.CH3CH2CH(Br)C6H4-OCH3\text{CH}_3\text{CH}_2\text{CH}(\text{Br})\text{C}_6\text{H}_4\text{-OCH}_3CH3CH2CH(Br)C6H4-OCH3d.CH3CH(Br)C6H4-Br\text{CH}_3\text{CH}(\text{Br})\text{C}_6\text{H}_4\text{-Br}CH3CH(Br)C6H4-BrLogin to continueOnly logged in users canattempt or see the solution.
