1.A double ordinate PQPQPQ of x2/a2−y2/b2=1x^2/a^2 - y^2/b^2 = 1x2/a2−y2/b2=1 is such that △OPQ\triangle OPQ△OPQ is equilateral. Then eee satisfiesa.1<e<2/31 < e < 2/\sqrt{3}1<e<2/3b.e=2/3e = 2/\sqrt{3}e=2/3c.e=3/2e = \sqrt{3}/2e=3/2d.e>2/3e > 2/\sqrt{3}e>2/3Login to continueOnly logged in users canattempt or see the solution.
