1.The Boolean expression ¬(p⇒(¬q))\neg(p \Rightarrow (\neg q))¬(p⇒(¬q)) is equivalent toa.¬p⇒q\neg p \Rightarrow q¬p⇒qb.q⇒¬pq \Rightarrow \neg pq⇒¬pc.p∨qp \lor qp∨qd.p∧qp \land qp∧qLogin to continueOnly logged in users canattempt or see the solution.
