1.The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile isa.θ=tan−1(1/4)\theta = \tan^{-1}(1/4)θ=tan−1(1/4)b.θ=tan−1(4)\theta = \tan^{-1}(4)θ=tan−1(4)c.θ=tan−1(2)\theta = \tan^{-1}(2)θ=tan−1(2)d.θ=45∘\theta = 45^\circθ=45∘Login to continueOnly logged in users canattempt or see the solution.
