1.The integrating factor of the differential equation dydx(xlogx)+y=2logx\frac{dy}{dx}(x\log x) + y = 2\log xdxdy(xlogx)+y=2logx is given bya.exe^xexb.logx\log xlogxc.log(logx)\log(\log x)log(logx)d.xxxLogin to continueOnly logged in users canattempt or see the solution.
