1.Let A=(12−14)A = \begin{pmatrix} 1 & 2 \\ -1 & 4 \end{pmatrix}A=(1−124). If A−1=αI+βAA^{-1} = \alpha I + \beta AA−1=αI+βA, where α,β∈R\alpha, \beta \in \mathbb{R}α,β∈R and III is the 2×22 \times 22×2 identity matrix, then 4(α−β)4(\alpha - \beta)4(α−β) is equal to:a.555b.12\dfrac{1}{2}21c.222d.444Login to continueOnly logged in users canattempt or see the solution.
