1.A particle is moving in a circular path. The acceleration and momentum of the particle at a certain moment are a⃗=(4i^+3j^) m/s2\vec{a} = (4\hat{i} + 3\hat{j})\,\text{m/s}^2a=(4i^+3j^)m/s2 and p⃗=(8i^−6j^) kg⋅m/s\vec{p} = (8\hat{i} - 6\hat{j})\,\text{kg·m/s}p=(8i^−6j^)kg⋅m/s. The motion of the particle isa.Uniform circular motionb.Accelerated circular motionc.De-accelerated circular motiond.We cannot say anything with a⃗\vec{a}a and p⃗\vec{p}p onlyLogin to continueOnly logged in users canattempt or see the solution.