1.For x2cos2α−y2sin2α=1\frac{x^2}{\cos^2\alpha} - \frac{y^2}{\sin^2\alpha} = 1cos2αx2−sin2αy2=1, what remains fixed when α\alphaα varies?a.directrixb.verticesc.focid.eccentricityLogin to continueOnly logged in users canattempt or see the solution.