1.If a,b∈Ra, b \in \mathbb{R}a,b∈R are such that 1−2i1 - 2i1−2i (here i2=−1i^2 = -1i2=−1) is a root of x2+ax+b=0x^2 + ax + b = 0x2+ax+b=0, then (a−b)(a - b)(a−b) is equal to:a.−7-7−7b.777c.−3-3−3d.333Login to continueOnly logged in users canattempt or see the solution.
