1.The number of solutions of the equation sin2x−2cosx+4sinx=4\sin 2x - 2\cos x + 4\sin x = 4sin2x−2cosx+4sinx=4 in the interval [0,5π][0, 5\pi][0,5π] isa.666b.444c.333d.222Login to continueOnly logged in users canattempt or see the solution.