1.The height at which the acceleration due to gravity becomes g/16g/16g/16 (where ggg = acceleration due to gravity on the surface of the earth) in terms of RRR is, if RRR is the radius of earth:a.2R2R2Rb.3R3R3Rc.2R\sqrt{2}R2Rd.3R\sqrt{3}R3RLogin to continueOnly logged in users canattempt or see the solution.