1.The equation of the conic with focus at (1,−1)(1, -1)(1,−1), directrix along x−y+1=0x - y + 1 = 0x−y+1=0 and with eccentricity 2\sqrt{2}2 isa.x2−y2=1x^2 - y^2 = 1x2−y2=1b.xy=1xy = 1xy=1c.2xy−4x+4y+1=02xy - 4x + 4y + 1 = 02xy−4x+4y+1=0d.2xy+4x−4y−1=02xy + 4x - 4y - 1 = 02xy+4x−4y−1=0Login to continueOnly logged in users canattempt or see the solution.
