1.If the distance between the foci of an ellipse is equal to the length of the latus rectum, then its eccentricity isa.14(5−1)\frac{1}{4}(\sqrt{5} - 1)41(5−1)b.12(5+1)\frac{1}{2}(\sqrt{5} + 1)21(5+1)c.12(5−1)\frac{1}{2}(\sqrt{5} - 1)21(5−1)d.14(5+1)\frac{1}{4}(\sqrt{5} + 1)41(5+1)Login to continueOnly logged in users canattempt or see the solution.
