1.The value of the limit limθ→0tan(πcos2θ)sin(2πsin2θ)\lim_{\theta \to 0} \frac{\tan(\pi \cos^2 \theta)}{\sin(2\pi \sin^2 \theta)}θ→0limsin(2πsin2θ)tan(πcos2θ) is equal to:Login to continueOnly logged in users canattempt or see the solution.
