1.A mixture of 1.0 mole of Al and 3.0 mole of Cl2_22 are allowed to react as: 2Al(s) + 3Cl2_22(g) →\rightarrow→ 2AlCl3_33(g). Then moles of excess reagent left unreacted is:a.3.5b.1.0c.1.5d.2.5Login to continueOnly logged in users canattempt or see the solution.