1.If xy=ex−yx^y = e^{x-y}xy=ex−y then dydx\frac{dy}{dx}dxdy is equal toa.logxlog(x−y)\frac{\log x}{\log(x-y)}log(x−y)logxb.exxx−y\frac{e^x}{x^{x-y}}xx−yexc.logx(1+logx)2\frac{\log x}{(1+\log x)^2}(1+logx)2logxd.1y−1x−y\frac{1}{y} - \frac{1}{x-y}y1−x−y1Login to continueOnly logged in users canattempt or see the solution.
