1.The approximate value of log10998\log_{10} 998log10998 is (given that log10e=0.4343\log_{10} e = 0.4343log10e=0.4343)a.3.00086863.00086863.0008686b.1.99913141.99913141.9991314c.2.00086862.00086862.0008686d.2.99913142.99913142.9991314Login to continueOnly logged in users canattempt or see the solution.
